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±?éè??μ?ìa???a?3?D????3μ?°?????ˉ?÷éè??￡?±?éè????ó??°???ìê????ˉ?ìê????ˉ?÷·??a?¨?ˉ?ìê?oí???ˉ?ìê??￡?ú3?·?á??a???ˉ?÷μ??á11?°1¤×÷?-àíμ??ù′?é??è?ú?à·???μ?×êá???DDéè???￠???¤?ù???¨?à1?2?êy2￠??DD????è·?¨??ì?2?êyè???￡o
???ˉá|·???￡??°?á???ˉá|Fu1=4486.3 N oó?á???ˉá| Fu2=9405.2 N
í?2???×??μêy￡? =0.7
???ˉ?÷D§?üòòêy￡?k=0.6
???ˉá|??￡o???ˉá|??ê????ˉ?÷2úéúμ?￡??èê1??3μ???ù?òí￡?1μ?×èá|??￡?óé??3μ?ù?üó?μ?μ?×?′ó??×??μêy ￡????ˉ???èq￡?3μ??óDD§°??? ￡???3μ?ú???êá?G￡???3μ?á?àL￡?í¨1y????μ?3?￡o?°??μ????ˉá|???aMu1=1358.15 N?m oó?????ˉá|??Mu2=497.2 N?m
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1??ü′ê￡o???ˉD??ü solidworks ?ìê????ˉ?÷


Abstract
The topic of this design for the design of the front wheel brake a intermediate car,this design selects the front disc brakedisc brake caliper disc is divided into fixed and floating caliper.On the basis of understanding the structure and working principle of the brake,with various materials to design,demonstrate the selected parameters and the calculation to determine the specific parameters are as follows:
The braking force distribution;front axle braking force Fu1=4486.3 Nthe rear axle braking force Fu2=9045.2 N.
The synchronous adhesion coefficient: =0.7
Brake effiency factor:k=0.6
Brake torque:Brake torque is generated by the brake, torque force car to slow down or stop,maximum adhesion coefficient can meet the vehicle ;severity of braking q￡?the effective radius re;The car loaded with quality G;the vehicle wheelbase L;calculation the front wheel brake toeque Mu1=1358.15 N?m,the rear wheel brake toeque Mu2=497.2 N?m
The design calculation of main parts size and material from the above parameters,the brake system performance requirements of applications,and use SolidWorks software to draw the parts of 3D model and the brake brake parts model.

Keywords￡o braking performance solidworks disc brake



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